Question: Given the following algorithm foo ( n ) if n < = 1 return 1 else x = foo ( n - 1 ) for

Given the following algorithm
foo(n)
if n <=1
return 1
else
x = foo(n-1)
for i =1 to n
x = x + i
return x
Determine the asymptotic running time. Assume that addition can be done in constant time.

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