Given the following answer and sensitivity reports

Objective Cell (Max)
	Cell	Name	Original Value	Final Value
	$D$11	profit per unit Total Profit	$2.1	$3,001.60
Variable Cells
	Cell	Name	Original Value	Final Value	Integer
	$B$8	units A	1	1005.33	Integer
	$C$8	units B	1	1994.66	Integer
Constraints
	Cell	Name	Cell Value	Formula	Status	Slack
	$D$14	Octane rating Lhs	80	$D$14>=$F$14	Binding	0
	$D$15	Gallons to run trucks Lhs	3000	$D$15>=$F$15	Binding	0
	$D$16	Storage capacity Lhs	3000	$D$16<=$F$16	Not Binding	1000
	$D$17	Availability of Fuel A Lhs	1005.333333	$D$17<=$F$17	Not Binding	994.6666667
	$D$18	Availability of Fuel B Lhs	1994.666667	$D$18<=$F$18	Not Binding	2005.333333

Variable Cells
			Final	Reduced	Objective	Allowable	Allowable
	Cell	Name	Value	Cost	Coefficient	Increase	Decrease
	$B$8	units A	1005.333333	0	1.2	1E+30	0.3
	$C$8	units B	1994.666667	0	0.9	0.3	1.5
Constraints
			Final	Shadow	Constraint	Allowable	Allowable
	Cell	Name	Value	Price	R.H. Side	Increase	Decrease
	$D$14	Octane rating Lhs	80	0.02	80	14920	15080
	$D$15	Gallons to run trucks Lhs	3000	1	3000	1000	2992
	$D$16	Storage capacity Lhs	3000	0	4000	1E+30	1000
	$D$17	Availability of Fuel A Lhs	1005.333333	0	2000	1E+30	994.6666667
	$D$18	Availability of Fuel B Lhs	1994.666667	0	4000	1E+30	2005.333333

The optimal solutions are A= __________ and B=__________. The optimal cost is __________.

Constraints __________ and __________ (1,2,3,4?) are working at full capacity. The unused capacity of the third constraint is _________.

If we add 100 units capacity to constraint 2 at a cost of $0.3 per unit, the amount of net benefit to the objective function is __________ dollars. (Keep two decimal points if needed.)