Question: Given the following code ( and assuming 8 - bit chars, 1 6 - bit ints, 3 2 - bit longs and floats, and 6

Given the following code (and assuming 8-bit chars, 16-bit ints, 32-bit longs and floats, and 64-bit doubles),
double *p;
p =(double *)(191);
p = p -3;
printf("%d", p);
What does the printf statement above print out?

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