Question: Given the following code char a[] = {'c', 'a', 't', '0'}; char *p = a; while (*p != 0) { *p = *p + 1;

Given the following code

char a[] = {'c', 'a', 't', '\0'}; char *p = a; while (*p != 0) { *p = *p + 1; printf("%c", *(p++)); }

What will happen?

A.

It prints: dbu
B.

It prints: a string of random characters
C.

It prints: cat
D.

A run time error will occur at this line.

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