Question: Given the following code; foo = 0 def bar ( foo ) : foo + = 5 if foo % 2 = = 0 :

Given the following code;
foo =0
def bar(foo):
foo +=5
if foo%2==0:
foo =-10
elif foo>0:
foo =1/0
What is foo after this code is ran?
Group of answer choices
Not enough information is possible to test the function.
5
An error occurs.
-10
0

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