Question: Given the following data: Cl 2 (g) + 5F 2 (g) 2ClF 5 (g) H=-510.0 kJ ClF 3 (g) + Cl 2 (g) 3ClF(g) H=-5.5
Given the following data:
| Cl2(g) + 5F2(g) 2ClF5(g) | H=-510.0 kJ |
| ClF3(g) + Cl2(g) 3ClF(g) | H=-5.5 kJ |
| Cl2(g) + F2(g) 2ClF(g) | H=-113.0 kJ |
calculate H for the reaction: ClF5(g) ClF3(g) + F2(g) H= 
Given the following data: Cl2(g)+5F2(g)2ClF5(g)H=510.0kJClF3(g)+Cl2(g)3ClF(g)H=5.5kJCl2(g)+F2(g)2CIF(g)H=113.0kJ calculate H for the reaction: ClF5(g)ClF3(g)+F2(g) H= Tries 0/5
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