Question: Given the following grammar: ::= | ; ::= = | + | * ::= x | 'x' | 'y' ::= ( ) | - |

Given the following grammar:

::= | ;

::= = | + | *

::= x | 'x' | 'y'

::= ( ) | - | 'z'

Are the following sentence valid?

xxyy = x*y; True or False?

xxxxy = y*z - z; True or False?

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