Given the following information:

$\backslash$table$[[,$Specific gravity,Dry Unit Weight,AC $(\%),$MC $(\%)],[$Cement$,3\mathrm{.}15,,,],[$Water$,1\mathrm{.}00,,,],[$Coarse Aggregate $($CA$),2\mathrm{.}68(BS{G}_{00}),96\mathrm{.}00l\frac{b}{f}{t}^3,0\mathrm{.}50,1\mathrm{.}70],[$Fine Aggregate $($FA$),2\mathrm{.}62(BS{G}_{00}),,0\mathrm{.}90,1\mathrm{.}20],[$Given conditions:,,,,$]]$

$\frac{W}{C}=0\mathrm{.}45$

Bulk volume of coarse aggregate per unit volume $(1$ yd $d^p)$ of concrete $=0\mathrm{.}67$

$4\mathrm{.}5\%$Air

$7$ sack mix with $25\%$ Fly ash $)=(2\mathrm{.}30$; the weight of one sack $=94lb$

Find:

Weight of Cement:

b

Weight of Fly Ash: lb

Weight of Water $($before moisture correction$)$:

b

Weight of Coarse aggregate $($before moisture correction$)$:

b

Volume of Cement cubic ft

Volume of Fly ash cubic ft

Volume of water cubic ft

Volume of air: cubic $ft$

Volume of coarse aggregate: cubic $ft$

Volume of Fine aggregate: cubic $ft$

Weight of Fine aggregate $($before moisture correction$)$ lb

Weight of coarse aggregate after moisture correction:

Weight of fine aggregate after moisture correction:

Weight of water after moisture correction