Question: Given the following LP and its optimal final tableau: max 2 1 + 2 - 3 . . 1 + 2 2 + 3 <

Given the following LP and its optimal final tableau:
max
2
1
+
2
-
3
.
.
1
+
2
2
+
3
<=
8
-
1
+
2
-
2
3
<=
4
1
,
2
,
3
>=
0
The optimal final tableau is shown below:
(
a
)
Suppose that the coefficient of
1
in the objective function has changed from
2
to
2
+
.
Determine for what values of
the current basis remains optimal.
(
b
)
Given the option to increase the RHS of the first constraint or the second constraint by
1
unit, which one would you choose and why?
(
c
)
Determine how many units
2
should increase such that there would be an alternate optimal
solution with
2
in the basis. How would you determine this value from the optimal tableau?
(
d
)
Find the set of RHS vectors such that the optimal basis includes variables
1
and
5
.
(
e
)
Suppose the following constraint is added to the problem:
2
+
3
=
5
.
What is the new
optimal solution? For each iteration explain which feasibility is lost.
(
f
)
A new activity
6
is proposed with a unit return of
6
and a consumption vector
6
=
(
2
,
1
)
.
Find the new optimal solution.

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