Question: Given the following polynomial, p(x) = 3x3 - 6x2 + 11x -8 1,2,4,8 According to the rational zero theorem, the possible zeros for p(x) are

Given the following polynomial, p(x) = 3x3 - 6x2 + 11x -8 1,2,4,8 According to the rational zero theorem, the possible zeros for p(x) are 1,3 It turns out x= 1 is a true zero of p(x). You can perform synthetic division to rewrite p(x) in the factored form given below. Find the values for a,b,c. p(x) = (x - 1)(ax

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