Question: Given the following poorly written code sequence: headPtr = new Node ( ) ; headPtr = NULL; What is the result? a . headPtr points

Given the following poorly written code sequence:
headPtr = new Node ();
headPtr = NULL;
What is the result?
a.
headPtrpoints to the new node
b.
You access the new node by use of headPtr
c.
The program crashes
d.
The new node is inaccessible

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