Question: Given the following segment of code: int a; int b; int c; if ( a % 2 ! = 0 ) { b = a

Given the following segment of code:
int a;
int b;
int c;
if (a %2!=0)
{
b = a *26;
if (a == b)
c = a + b;
else if (a < b)
c = b a;
else
c =25;
}
else if (a <6)
b =3* a;
c = b /2;
else if (a >20)
{
c =5;
b = a 3;
if ((b > c) && (b < c))
a =2* c -1;
else if ((b > c)||(b < c))
a =3- b;
else
a = b / c;
}
else
{
c =6* a;
b = a + c;
}
What are the final values of a, b, and c when the initial value of a is 8?

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