Given the following two method signatures, explain the reasoning behind how the C# compiler determines which...

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Given the following two method signatures, explain the reasoning behind how the C# compiler determines which method version to invoke for the call MyMethod(12) (note: assume both methods coexist): private static void MyMethod(int a) private static void MyMethod (int a, char b = 'B') The first version is better because no optional parameter are omitted The second version is better because there are optional parameters Both method signatures are equal None of the method signatures are valid Given the following two method signatures, explain the reasoning behind how the C# compiler determines which method version to invoke for the call MyMethod(12) (note: assume both methods coexist): private static void MyMethod(int a) private static void MyMethod (int a, char b = 'B') The first version is better because no optional parameter are omitted The second version is better because there are optional parameters Both method signatures are equal None of the method signatures are valid

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The correct choice for the above question is option a that is The first version is better because no ... View the full answer