Given the function below:

uint$16\_$t factorial$($uint$16\_$t n$)$

$\{$

if $($n $==0)$

return $1$;

else

return$($n $*$ factorial$($n$-1))$;

$\}$

If the function is called as below, how many times does this result in the factorial$()$ function being called?

uint$16\_$t result $=$ factorial$(6)$;

Group of answer choices

$0$

$1$

$2$

$3$

$4$

$5$

$6$

$7$

$8$

$9$

$10$