Question: . Given the function f, prove that f is one-to-one using the definition of a one-to-one function. a)f(x) = 1/3x - 6 b)f(x) = x

. Given the function f, prove that f is one-to-one using the definition of a one-to-one function.

a)f(x) = 1/3x - 6

b)f(x) = x3 +

3.Given the function g, prove that g is not one-to-one using the definition of a one-to-one function.

a)g(x) = 1 - x2

b)g(x) = x4 - x2

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