Given the function table below, obtain a canonical SOP equation for F$1.($Note: for ease of entering the response, please use a $$tick mark,$()$ instead of an overbar to denote a complement. $\backslash$begin$\{$tabular$\}\{|$c$|$c$|$c$|$c$|$c$|\}$

$\backslash$hline $\backslash (\backslash$mathbf$\{$A$\}\backslash )$ & $\backslash (\backslash$mathbf$\{$B$\}\backslash )$ & $\backslash (\backslash$mathbf$\{$C$\}\backslash )$ & $\backslash (\backslash$mathbf$\{$D$\}\backslash )$ & $\backslash (\backslash$mathbf$\{$F$\}\_\{\backslash$mathbf$\{1\}\}\backslash )\backslash \backslash$

$\backslash$hline $0$ & $0$ & $0$ & $0$ & $0\backslash \backslash$

$\backslash$hline $0$ & $0$ & $0$ & $1$ & $1\backslash \backslash$

$\backslash$hline $0$ & $0$ & $1$ & $0$ & $1\backslash \backslash$

$\backslash$hline $0$ & $0$ & $1$ & $1$ & $0\backslash \backslash$

$\backslash$hline $0$ & $1$ & $0$ & $0$ & $1\backslash \backslash$

$\backslash$hline $0$ & $1$ & $0$ & $1$ & $0\backslash \backslash$

$\backslash$hline $0$ & $1$ & $1$ & $0$ & $0\backslash \backslash$

$\backslash$hline $0$ & $1$ & $1$ & $1$ & $1\backslash \backslash$

$\backslash$hline $1$ & $0$ & $0$ & $0$ & $0\backslash \backslash$

$\backslash$hline $1$ & $0$ & $0$ & $1$ & $0\backslash \backslash$

$\backslash$hline $1$ & $0$ & $1$ & $0$ & $0\backslash \backslash$

$\backslash$hline $1$ & $0$ & $1$ & $1$ & $1\backslash \backslash$

$\backslash$hline $1$ & $1$ & $0$ & $0$ & $0\backslash \backslash$

$\backslash$hline $1$ & $1$ & $0$ & $1$ & $0\backslash \backslash$

$\backslash$hline $1$ & $1$ & $1$ & $0$ & $0\backslash \backslash$

$\backslash$hline $1$ & $1$ & $1$ & $1$ & $1\backslash \backslash$

$\backslash$hline

$\backslash$end$\{$tabular$\}$