Question: Given the function, $y=y(x) $ below, find $y^{prime} $ and evaluate at $x=0$. $$ y(x)=frac{(1+2 x)^{1 / 2} (1+4 x)^{1 / 4](1+6 x)^{1 / 6](1+8

 Given the function, $y=y(x) $ below, find $y^{\prime} $ and evaluate

Given the function, $y=y(x) $ below, find $y^{\prime} $ and evaluate at $x=0$. $$ y(x)=\frac{(1+2 x)^{1 / 2} (1+4 x)^{1 / 4](1+6 x)^{1 / 6](1+8 x)^{1 / 8}}{(1+3 x)^{1 / 3} (1+5 x)^{1 / 5)(1+7 x)^{1 / 7)(1+9 x)^{1 / 9}}, $$ CS.JG. 106

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