Given the integral:

${\displaystyle \underset{4}{\overset{16}{}}}\frac{sin(\sqrt[\phantom{2}]{x})}{\sqrt[\phantom{2}]{x}}dx$

And the substitution:

$u=\sqrt[\phantom{2}]{x}$

Fill in the blank on the equivalent integral.

$-{\displaystyle \underset{2}{\overset{4}{}}}sin(u)du$