Question: Given the project network and time (in days) and cost information listed below, what is the lowest possible cost after expediting the project by 3

  1. Given the project network and time (in days) and cost information listed below, what is the lowest possible cost after expediting the project by 3 days? (CBC = Cannot be crashed.Given the project network and time (in days) and

Activity

Normal Time

Crash Time

Normal Cost

Crash Cost

A

1

CBC

$400

CBC

B

3

2

$600

$700

C

5

2

$300

$1200

D

6

4

$200

$1000

E

4

2

$500

$800

F

2

1

$600

$800

A. $2900 B. $3100 C. $3300 D. $3400 E. $3600

  1. In a G/G/1 queue, the average arrival rate is 10 customers per hour and the standard deviation of inter-arrival times is 12 minutes. The service time is 3 minutes per customer and its standard deviation is zero. The average queue length is:

A. 1/3 B. 1/2 C. 1 D. 2 E. None of the above

  1. Consider a process consisting of two activities with different unit loads shown below (s for second): Given the project network and time (in days) and

To double the output per hour, you can

A. Buy one more Machine 1 for Activity 1 (working in parallel)

B. Replace Machine 2 with a faster machine which cuts the unit load by half

C. Buy one more Machine 2 for Activity 2 (working in parallel)

D. Both B and C; E. None of the above

AT > Activity 1 Machine 1 >Activity 2 Machine 2 10s 85

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