Question: Given the recurrence relation T(n) = 4T(n/2) + n with T(0) = 1, then T(n) = theta(log n) theta(n) theta(n log n) theta(n^2) theta(n^2 log

Given the recurrence relation T(n) = 4T(n/2) + n with T(0)

Given the recurrence relation T(n) = 4T(n/2) + n with T(0) = 1, then T(n) = theta(log n) theta(n) theta(n log n) theta(n^2) theta(n^2 log n) none of these Given the recurrence relation T(n) = 4T(n/2) + n^2 with T(0) = 1, then T(n) = theta(log n) theta(n) theta(n log n) theta(n^2) theta(n^2 log n) none of these

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