Given the time and velocity matrices below, solve for the K$1$and K$2$coefficients in the equaition. This is using advanced engineering analysis. I think the best way to solve this is to use ode$45($or rk$4$sys$)$and fsolve at the same time. Use MatLab to complete this and upload your answer as a MatLab code $($type the code out$).$

The data is from a bobled competition and given is $4$ teams each doing $4$ races. It is only the first $50$ meters of the race. So the data is as follows:

Team $($A$)$ and Race $(1)$

so:

t $=[$A$1$ A$2$ A$3$ A$4$

B$1$ B$2$ B$3$ B$4$

C$1$ C$2$ C$3$ C$4$

D$1$ D$2$ D$3$ D$4]$;

The same goes for the velocity matrix.

The time is the time it takes each team to complete $50$ meters, and the velocity at that time.

So the span would be $[050]$

t $=[$

$4\mathrm{.}954\mathrm{.}944\mathrm{.}934\mathrm{.}97$

$5\mathrm{.}014\mathrm{.}975\mathrm{.}045\mathrm{.}02$

$5\mathrm{.}115\mathrm{.}125\mathrm{.}165\mathrm{.}10$

$5\mathrm{.}065\mathrm{.}085\mathrm{.}085\mathrm{.}07]$;

v $=[$

$48\mathrm{.}8449\mathrm{.}1649\mathrm{.}2048\mathrm{.}84$

$48\mathrm{.}4248\mathrm{.}8048\mathrm{.}3348\mathrm{.}67$

$48\mathrm{.}1247\mathrm{.}8147\mathrm{.}7648\mathrm{.}19$

$48\mathrm{.}6148\mathrm{.}1148\mathrm{.}0048\mathrm{.}10]$;

$\frac{d^{2}x}{d{t}^2}=K_1\frac{dx}{dt}+K_2$