Question: - Given Values - - Atomic Radius ( n m ) = 0 . 1 3 9 F C C Metal = Lead B C

-Given Values--
Atomic Radius (nm)=0.139
FCC Metal = Lead
BCC Metal: = Cesium
Temperature (C)=1450
Metal A= Iron
Equilibrium Number of Vacancies (m-3)=1.00E+23
Temperature for Metal A(C)=283
Metal B = Copper
If the atomic radius of a metal is the value shown above and it has the face-centered cubic crystal structure, calculate the volume of its unit cell in nm3? Write your answers in Engineering Notation.
Your Answer =q,
What is the atomic packing factor for the BCC crystal structure?
Your Answer =C
Find the theoretical density for the FCC Element shown above in gcm3. Write your answer to the ten thousandths place (0.0000) :
Your Answer =q,
Calculate the atomic radius, in nm , of the BCC Metal above utilizing the density and the atomic weight provided by examination booklet - Write your answer with 4 significant figures:
Your Answer =q,
Calculate the fraction of atom sites that are vacant for copper (Cu) at the temperature provided above. Assume an energy for vacancy formation of 0.90eV? atom:
Your Answer =q,
Repeat the calculation in question 5 at room temperature (25C) :
Your Answer =q,
Calculate the energy (in eV? atom) for vacancy formation for the Metal A and the equilibrium number of vacancies at the temperature provided above - Write your answer with 4 significant figures:
Your Answer =q,
Calculate the number of atoms per cubic meter in Metal B (units atoms ?m3). Write your answer with 4 significant figures :
Your Answer =q,
What is the composition, in atom percent, of an alloy that contains a)36 g Metal A and b)47 g Metal B? Composition for Metal A(%):
Your Answer =
What is the composition, in atom percent, of an alloy that contains a)36 g Metal A and b)47 g Metal B? Composition for Metal B (%):
Your Answer =
What is the composition of Metal A in atom percent, if the alloy consists of 4.5wt%MlA and 95.5wt% of Metal B?
Your Answer =
What is the composition of Metal B in atom percent, if the alloy consists of 4.5 wt % Metal A and 95.5 wt % of Metal B? Your Answer =
Your Score =0100
83%F
- Given Values - - Atomic Radius ( n m ) = 0 . 1

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