Given $y_p=\frac{1}{9}{t}^2\frac{4}{27}t\frac{2}{27}$ is a particular solution of $y^{\text{'}\text{'}}-6y^{\text{'}}9y=t^{\text{'}},$

find the general solution. Use lowercase $c_1$ and $c_2$ as the arbitrary constants.

$v(t)=$

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