Given y=(x+2)(2r2+3)3 find the equation of the tangent line to this function when x = 1....

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Given y=(x+2)(2r2+3)3 find the equation of the tangent line to this function when x = 1. First find the point on this function and the slope of the tangent line to this function when x = 1. Next use these to find the equation of the tangent line to this function when x = 1. Finally, put this equation in slope intercept form. All work must be shown!! %3D %3D Point on function when x = 1 is (1, Slope of tangent line when x = 1 is Equation of tangent line in slope intercept form is: Given y=(x+2)(2r2+3)3 find the equation of the tangent line to this function when x = 1. First find the point on this function and the slope of the tangent line to this function when x = 1. Next use these to find the equation of the tangent line to this function when x = 1. Finally, put this equation in slope intercept form. All work must be shown!! %3D %3D Point on function when x = 1 is (1, Slope of tangent line when x = 1 is Equation of tangent line in slope intercept form is:

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hope it helps you Solution 11 briven Point on function Y m 3 y x 2 2 x 4 3 22 2 1 3 3 233 3 ... View the full answer