Question: Graph the function f(x)=-2x^2 and draw the tangent lines to the graph at points whose x-coordinates are -2,0, and 1.10+.378 ing 432}-4-2-21-3-6-7-3-9+ Clear All Draw:
Graph the function f(x)=-2x^2 and draw the tangent lines to the graph at points whose x-coordinates are -2,0, and 1.10+.378 ing 432}-4-2-21-3-6-7-3-9+ Clear All Draw: Find the difference quotient f(x + h)- f(x) h Find f'(x) by determining lim h+0 f(x +h)-f(x) h Find f'(-2)(This slope should match the tangent line you drew above.) Find f'(o) Find f'(1) Graph the function f(x)=2x -3 and draw the tangent lines to the graph at points whose x-coordinates are -2,0, and 1.43211-5-4134-3-2-1-15-3-4-5 Clear All Draw: FA f(x+h)-f(x) Find the difference quotient h f(x +h)-f(2) Find f'(x) by determining lim h h>0 Find f'(-2)(This slope should match the tangent line you drew above.) Find f'(0) Find f'(1) The graph of f(x) is shown below. Estimate and list the value of x where f(x) has a horizontal tangent. 5432184-691610-9-8-7-6-5-4-3-2-2-1-3-4 x = If f(x)=17, find f'(-5). If f(x)=2+5x -4x?, find f'(1). 2 If f(x) find f'(1). If h(x)=6-42", find h'(1). Use this to find the equation of the tangent line to the curve y =6-4x at the point (1,2). The equation of this tangent line can be written in the form y = mx + b where m is: and where b is:
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