Graph the parabola. Specify the focus, directrix, and focal width. y2-8y-4x-12=0 Find the equation of the parabola satisfying the given conditions. Assume that the vertex is at the origin. The focus is (0, 7). OA y = 28x OB x = 28y OC y = -28x OD x2 = -28y If the equation of a parabola is x = 4py, the the focus is at OA (-p, 0) OB (0, - p) OC (p, 0) OD (0, p) Two sides and an angle (SSA) are given. Determine whether the given information results in one triangle, two triangles, or no triangle at all. Solve any triangle(s) that result(s). a = 7, b = 9, B = 49 OA one triangle A = 35.94 C = 95.06 C = 11.88 OB one triangle A = 76.01 C = 54.99 C = 7-60 OC two triangles A = 76.01 C = 54.99 C1 = 7.60 or A = 103.99 C = 27.01 C = 12.14 OD no triangle O Solve the equation on the interval 00