Question: The product of the first five natural numbers is, 1.2.3-4.5 = 5! = 120 %3D The square of the sum of the first five
The product of the first five natural numbers is, 1.2.3-4.5 = 5! = 120 %3D The square of the sum of the first five natural numbers is, (1+2 +3+4 + 5)2 = 152 = 225 Hence the difference between the product of the first ten natural numbers and the square of the sum is 120 - 225 = -105. Find the difference between the product of the first fifty natural numbers and the square of the sum of the first fifty natural numbers.
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