$\begin{array}{cc}H& 2\end{array}$

Use the Laplace transform $to$ solve

$y^{\text{'}\text{'}}-y=sin(t),y(0)=0,y^{\text{'}}(0)=1$

$It$ might $be$ helpful $to$ notice that

$\frac{s^2+2}{(s-1)(s+1)(s^2+1)}=\frac{1}{2(s-1)}+\frac{1}{2(s+1)}-\frac{s}{s^2+1}.$