$*HHV(M\frac{J}{k}g)=0\mathrm{.}339C+1\mathrm{.}44H-0\mathrm{.}139O+0\mathrm{.}105S$

$*LHV=(HHVinM\frac{J}{k}g)-0\mathrm{.}0244(W+9H)$ A sample of completely combustible carbonaceous waste has an empirical

formula of C$70\mathrm{.}3$H$116\mathrm{.}6$O$35\mathrm{.}8$Cl$0\mathrm{.}7$N$1\mathrm{.}8$S$0\mathrm{.}6.$ Proximate analysis of the waste revealed

that it had a moisture content $4\mathrm{.}6\%.$ Complete combustion of the waste requires

$117$ m$3$ of air to be flowed through the material.

Calculate the HHV and LHV of the waste.