Question: H . w t 2 y ' ' - 2 y = t 3 given that y 1 ( t ) = 1 t is

H.w
t2y''-2y=t3
given that y1(t)=1t is the solution of the honogerous equation
H.w
t2y''-2y=t3
given that y1(t)=1t is the solution of the honogerous equation
H.w
t2y''-2y=t3
H . w t 2 y ' ' - 2 y = t 3 given that y 1 ( t )

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