Hailstone sequence

Given a positive integer n$,$ the following rules will always create a sequence that ends with $1,$ called the hailstone sequence:

If n is even, divide it by two

If n is odd, multiply it by $3$ and add $1($i$.$e$.3$n $+1)$

Continue until n is $1$

Write a program that reads an integer as input and prints the hailstone sequence starting with the integer entered. Format the output so that ten integers, each separated by a tab character $(\backslash$t$),$ are printed per line. End the last line of output with a new line $($endl$).$

The output format can be achieved as follows:

cout $$ n t$"$;

Ex: If the input is: $25$

The output is:

$25763819582988442211$

$3417522613402010516$

$8421$

FIX MY CODE PLEASE, SOME INPUTS HAVE ISSUES

#include

using namespace std;

int main$()$

$\{$

int n$,$ count $=1$;

cin $>>$ n;

cout $$ n t$"$;

while$($ n $>1)$

$\{$

if $($ n$\%2==0)$

n $/=2$;

else

n $=3*$ n $+1$;

cout $$ n t$"$;

$++$count;

if $($ count $\%10==0)$

$\{$

cout $$ endl;

$\}$

$\}$

cout $$ endl;

$\}$