2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups...

 

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2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups will be inspected randomly with number of broken cups recorded. i. with use of suitable approximation, find probability when 8-15 of cups are broken if 100 cups are inspected. ii. cups will be returned when 20 cups is inspected and more than 10% are broken. find the probability that the cups will not be returned. iii. Last time the probability of broken cups is 0.02. This time it is 0.0511 and will be returned. Use the suitable approximation, find maximum number of broken cups when there are 200 cups so that it will not be returned. 2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups will be inspected randomly with number of broken cups recorded. i. with use of suitable approximation, find probability when 8-15 of cups are broken if 100 cups are inspected. ii. cups will be returned when 20 cups is inspected and more than 10% are broken. find the probability that the cups will not be returned. iii. Last time the probability of broken cups is 0.02. This time it is 0.0511 and will be returned. Use the suitable approximation, find maximum number of broken cups when there are 200 cups so that it will not be returned. 2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups will be inspected randomly with number of broken cups recorded. i. with use of suitable approximation, find probability when 8-15 of cups are broken if 100 cups are inspected. ii. cups will be returned when 20 cups is inspected and more than 10% are broken. find the probability that the cups will not be returned. iii. Last time the probability of broken cups is 0.02. This time it is 0.0511 and will be returned. Use the suitable approximation, find maximum number of broken cups when there are 200 cups so that it will not be returned. 2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups will be inspected randomly with number of broken cups recorded. i. with use of suitable approximation, find probability when 8-15 of cups are broken if 100 cups are inspected. ii. cups will be returned when 20 cups is inspected and more than 10% are broken. find the probability that the cups will not be returned. iii. Last time the probability of broken cups is 0.02. This time it is 0.0511 and will be returned. Use the suitable approximation, find maximum number of broken cups when there are 200 cups so that it will not be returned. 2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups will be inspected randomly with number of broken cups recorded. i. with use of suitable approximation, find probability when 8-15 of cups are broken if 100 cups are inspected. ii. cups will be returned when 20 cups is inspected and more than 10% are broken. find the probability that the cups will not be returned. iii. Last time the probability of broken cups is 0.02. This time it is 0.0511 and will be returned. Use the suitable approximation, find maximum number of broken cups when there are 200 cups so that it will not be returned. 2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups will be inspected randomly with number of broken cups recorded. i. with use of suitable approximation, find probability when 8-15 of cups are broken if 100 cups are inspected. ii. cups will be returned when 20 cups is inspected and more than 10% are broken. find the probability that the cups will not be returned. iii. Last time the probability of broken cups is 0.02. This time it is 0.0511 and will be returned. Use the suitable approximation, find maximum number of broken cups when there are 200 cups so that it will not be returned. 2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups will be inspected randomly with number of broken cups recorded. i. with use of suitable approximation, find probability when 8-15 of cups are broken if 100 cups are inspected. ii. cups will be returned when 20 cups is inspected and more than 10% are broken. find the probability that the cups will not be returned. iii. Last time the probability of broken cups is 0.02. This time it is 0.0511 and will be returned. Use the suitable approximation, find maximum number of broken cups when there are 200 cups so that it will not be returned. 2. Cups may break at some point at shipment, probability of it breaking is 0.20. Cups will be inspected randomly with number of broken cups recorded. i. with use of suitable approximation, find probability when 8-15 of cups are broken if 100 cups are inspected. ii. cups will be returned when 20 cups is inspected and more than 10% are broken. find the probability that the cups will not be returned. iii. Last time the probability of broken cups is 0.02. This time it is 0.0511 and will be returned. Use the suitable approximation, find maximum number of broken cups when there are 200 cups so that it will not be returned.

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