Question: HASKELL assignment (without using any imports) given the function : lapp :: Int->[String]->[String] lapp i [] = [] lapp i (x:xs) = (concat(take i(repeat x))

HASKELL assignment (without using any imports)

given the function :

lapp :: Int->[String]->[String]

lapp i [] = []

lapp i (x:xs) = (concat(take i(repeat x)) : lapp i xs)

-- end of function

Use "foldr" to define "fapp" which completes the equation: fapp f xs = lapp f xs.

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