Question: HB ( feed vapor ) = 3 1 . 1 kj / mol HT ( feed vapor ) = 3 5 . 5 5 kj

HB(feed vapor)=31.1 kj/mol
HT(feed vapor)=35.55 kj/mol
HB(product vapor)=30.17 kJ/mol
HT(product vapor)=4.38 kJ/mol
Calculate the heat removed by the process using the energy balance
equation.Q=-2,172 kJ/s The answers are listed please show me how to get them!
T
HB(feed vapor)=31.1 kj/mol HT(feed vapor)=35.55 kj/mol HB(product vapor)=30.17 kJ/mol HT(product vapor)=4.38

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