he $0\mathrm{.}5$ in diameter rod $CE$ and the $0\mathrm{.}75$ in diameter rod $DF$ are attached to the rigid

ember ABCD as shown. The two rods are made of aluminum.

$=10{10}^3$ksi

a$)$ Determine the stresses in rods $CE$ and $FD.$

b$)$ Determine the deflection at $A.$

$10(30)=0$

$G{\displaystyle \underset{?}{\overset{?}{}}}{M}_D=0$

$F_{CE}(8)+10(38)=0$

$F_{CE}=47\mathrm{.}5$

$7*5$

$F_{CE}(8)+10(38)=0$