He, I need help with these 2 problems below. Please if you can show the work that will be great.

B webassignmet In TU anorma pro-ual P0 e 0 (3an sampeo o-serva OI'ISO 003 I19 0.83 0.87 0.87 1.05 1.11 1.14 1.27 1.30 1.47 1.49 1.60 1.60 1.66 1.69 1.76 1.82 Determlne the z percentlle assoclated wlth each sample observatlon. (Round your answers to two declmal places.) Sample observation 0.83 0.87 0.87 1.05 1.11 1.14 1.27 1.30 2 percentile ' ' Sample observation 1.47 1.49 1.60 1.60 1.66 1.69 1.76 1.82 2 percentile Choose the plot that best represents the normal probability plot for the sample of observations. thickness thickness thickness Would you feel comfortable estimating population mean thickness using a method that assumed a normal population distribution? A Yes, the probability plot is reasonably straight. A Yes, the probability plot is not straight. A No, the probability plot is reasonably straight. A No, the probability plot is not straight. digitJ L7,, ,, ,, .7... Low V febassigninel 0' LLQJLE Need Help? Let X denote the number of Canon SLR cameras sold during a particular week by a certain store. The pmf ofX is X 0 1 2 3 4 Px(x) 0.1 0.2 . 0.25 0.15 Sixtyve percent of all customers who purchase these cameras also buy an extended warranty. Let Ydenote the number of purchasers during this week who buy an extended warranty. (a) What Is P(X = 4, Y = 2)? [Hint This probability equals P(Y = 2|X = 4) ' P(X = 4); now think of the four purchases as four trials of a binomial experiment, with success on a trial corresponding to buying an extended warranty.] (Round your answer to four decimal places.) P(X = 4, Y = 2) = (b) Calculate P(X = Y). (Round your answer to four decimal places.) P(X=Y)=i. , i (c) Determine the joint pmf ofX and Y. O (;)(0.65)"(0.35)X'Y - px(x) Q ('y')(o.55)Y(0.35y'-Y - pX(x) Q (:)(0.65)y(0.65)x'y - px(x) Q (:)(0.55)X(0.65y'-Y - px(x) Determine the marginal pmf of Y. (Round your answers to four decimal places.) y o 1 2 3 4 My) i \\ You may need to use the appropriate table In the Appendix of Tables to answer this question. Need Hem