he MAD for the forecast developed using a weighted$2-$year moving average with weights of $0\mathrm{.}45$ and $0\mathrm{.}55=$

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$125\mathrm{.}8$ miles $($round your response to one decimal$$ place$).($Hint: You will have only $3$ years of matched$$ data.$)$

Part $6$

$$d$)$ Using exponential smoothing with alpha $=0\mathrm{.}20$ and the forecast for year $1$ being $3$ comma $000,$ the forecast for year $6=$

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$3424$ miles $($round your response to the nearest whole$$ number$).$