Question: head/OxA-> 0/0xE--> 1/0xD --> 2/NULL A new node is inserted at the start of the list. Assume the new node stores number 5 and
head/OxA-> 0/0xE--> 1/0xD --> 2/NULL A new node is inserted at the start of the list. Assume the new node stores number 5 and it is allocated memory address OxF. What are the contents of the new list? Choose ONE option: O None of these answers O head/0xF-> 5/0xA -> 2/0xE-> 3/0xD -> O/NULL O head/0xF--> 5/0xA --> 0/0xE--> 1/0xD -> 2/NULL head/0xF-> 0/0xE-> 1/0xD -> 2/0xXA -> 5/NULL O head/OxA-> 0/0xE-> 1/0xD -> 2/NULL --> 5/0xF O 0/0xF-> head/0xA --> 1/0xE- --> 2/0xD -> 5/NULL
Step by Step Solution
3.44 Rating (157 Votes )
There are 3 Steps involved in it
The detailed answer f... View full answer
Get step-by-step solutions from verified subject matter experts
