Question: Helium gas ) = ( 5 . 2 ( k J ) * K g - 1 * K - 1 undergoes a change of

Helium gas )=(5.2(kJ)*Kg-1*K-1 undergoes a change of state from 100kPa and 25C to 500kPa and 250C. Assuming the gas obeys the following equation of state: P(V-a)=RT; where a=0.01m3*kg-1, determine the change in the enthalpy (in kJ*kg-1), and entropy (in kJkg-1*K-1) by:
a- Using (eq.6.21) and (eq.6.22)
b- Using the ideal gas state combined with (eq.6.46) and (eq.6.48)
 Helium gas )=(5.2(kJ)*Kg-1*K-1 undergoes a change of state from 100kPa and

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