Hello again,

In my previous question, perhaps I was incorrect the way I presented the question.

Attached is a modification of the similar question without the Force F$1$ but now shown as Force AB$.$

In a previous similar question, the Force AB was at $45$ degrees, therefore the Sin $45$ Cos $45$ cancelled each other out. Now the angles are $21\mathrm{.}04$ and $3\mathrm{.}05$ degrees so it appears the Sin Cos will not cancel, so I am stuck as how to proceed with this. $??$

Your previous solution shows that after solving equation $($i$)$ and $($ii$)$ that F$1$ & Fp and I have been unable to come up with similar solution.

Can you please further explain $?$

Please see attached.

$F_{AB}(sin21\mathrm{.}04)-F_p(sin3\mathrm{.}05)-F_{AB}(cos21\mathrm{.}04)-F_p(cos3\mathrm{.}05)=422$