Hello, can you please draw the graph that I can understand quickly, help me with the Math ? Thanks a lot!

For each of the following points, determine the abscissas at which the graphs of the functions f and g admit parallel tangents
(a) f(x) = 3x² - 5x + 7 and g (x) = x-4

Q.1 : Can I use f(x) = g(x) instead of f'(x) = g'(x) --> 3x² - 5x + 7 = x-4 to find x

Q.2 : can you please show abscissas and parallel tangents on the graph that I can understand quickly please! Thanks a lot

Step 2/2 We have, The abscissas at which the graphs of the functions 1 and g admit parallel tangents can be determined by solving the equation f'(x) = g'(x), where f'(x) and g'(x) denote the derivatives of f and g, respectively. For the given functions f(x) = 3x2-5x+7 and g(x) = x - 4, the derivatives are f'(x) = 6x - 5 and g'(x) = 1. Thus, the equation to solve is 6x - 5 = 1, which yields x = 1/3 Therefore, the abscissas at which the graphs of the functions f and g admit parallel tangents is x = 4/3. Explanation Please refer to the steps of solution Final answer the abscissas at which the graphs of the functions f and g admit parallel tangents is x = 4/3. This is required results