Question: Hello: I am having difficulty with this question: Assume that, on average, healthy young adults dream 90 minutes each night, as inferred from a number
Hello:
I am having difficulty with this question:
Assume that, on average, healthy young adults dream 90 minutes each night, as inferred from a number of measures, including rapid eye movement (REM) sleep. An investigator wishes to determine whether drinking coffee just before going to sleep affects the amount of dream time. After drinking a standard amount of coffee, dream time is monitored for each of 28 healthy young adults in a random sample. Results show a sample mean, X, of 88 minutes and a sample standard deviation, s, of 9 minutes.
(a) Use t to test the null hypothesis at the .05 level of significance
(b) If appropriate (because the null hypothesis has been rejected), construct a 95 per-cent confidence interval and interpret this interval
This is what I calculated, but I don't believe it is correct:
Ho: mu=90
H1: mu90
Our one sample t-test statistic is t=88-90/(9/28)=2/1.701=- 1.175
28-1=27 e. p-value=P(t> -1.1759)=0.12495 p=2 *0.12495=0.2499 p-
value=0.2499
The null hypothesis has not been rejected, so there is no need to construct a 95% confidence interval.
Thank you for your help!
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