Hello, I don't understand why am I wrong for the very last part. Please explain :) Thank you!

Suppose that x is a binomial random variable with n = 5, p = 0.6, and q = .40. (b) For each value of x, calculate p(x). (Round final answers to 4 decimal places.) p(0) = 0.0102 , P(1) = p(4) = 0.2592 0, p(5) = 0.0768 , p(2) = 0.2304 , p (3) = 0.3456 0 0.0778 (c) Find P(x = 3). (Round final answer to 4 decimal places.) P(x=3) 0.3456 0 (d) Find P(x 5 3). (Do not round intermediate calculations. Round final answer to 4 decimal places.) P(x 5 3) 0.663 0 (e) Find P(x 2). (Do not round intermediate calculations. Round final answer to 4 decimal places.) P(x > 2) 0.6826 0 (h) Use the probabilities you computed in part b to calculate the mean ,, the variance, of , and the standard deviation, ax, of this binomial distribution. Show that the formulas for My , x, and , given in this section give the same results. (Do not round intermediate calculations. Round final answers to My in to 2 decimal places, x and ox in to 4 decimal places.) HX 3.00 1.2 0 1.0950 (i) Calculate the interval [x 1 20,]. Use the probabilities of part b to find the probability that x will be in this interval. Hint: When calculating probability, round up the lower interval to next whole number and round down the upper interval to previous whole number. (Round your answers to 4 decimal places. A negative sign should be used instead of parentheses.) The interval is ( 0.8100 , 5.1900 @]. P 1.0000 0 s x S 5.0000 ) = 0.9898