Question: Hello, I have this problem on my most recent calculus homework. I was hoping you could help me double check my answers- Any response is

Hello, I have this problem on my most recent calculus homework.
I was hoping you could help me double check my answers-
Any response is greatly appreciated, thank you!
**I apologize in advance for the long question. You may simplify and shorten if you wish.

Based on data from a research group, a model for the total stopping distance of a moving car in terms of its speed is s = 1.6v + 0.067v-, where s is measured in ft and v in mph. The linear term 1.6v models the distance the car travels during the time the driver perceives a need to stop until the brakes are applied, and the as quadratic term 0.067v models the additional braking distance once they are applied. Find - " at v = 40 and v =75 mph, and interpret the meaning of the derivative. ft. hr. ds At v = 40 mph, = dy mph. ds ft/mph. At v = 75 mph, dy Interpret the derivative. Choose the correct answer below. O A. The derivative represents the distance traveled by the car in feet for a velocity in mph. O B. The derivative represents the additional number of feet needed to stop a car for a 1 mph increase in the speed. O C. The derivative represents the total time needed for the car to completely stop. O D. The derivative represents the deceleration of the car after the driver applies the brakes
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