hello, i need the answer ASAP I NEED TO ASK THE BELOW DIFFRANTIATING OF LOG BASE 10 OR BASE E

Q# 02 page Hol calculate the expected percentage error in the time period, calculation if your measurement of length is 4% high. Solution we know that T = On Ja Taking logarithm on both sides we get log T = log ( 2 7 J /g ) = 7 logT = logan+ log ( lig ) "2 (1 . : logcab) = loga +logb = 7 lost = log (on ) + + log ( eng ) .. logo = bloga = log(on ) + z loge -2 logg. ( 1 ) differentiating Us using total differential we get IdT = 0+ +xy x de - 1x qx dg This can be written as dT x 100 ) = 1 ( 2 x 100) - 1 (29 x 100) L ( 2 ) where 1 x 100 ) = % error in measuring ( ' (23 x 100 ) is % error in measuring 9 and