Hello,

I would need help on this assignment.

Below are the questions:

1. Construct a 95% confidence interval estimate of the standard deviation of the males.

2. Test the claim that there is no difference in the variances for males and females.Use

5% level of significance. Use the critical value approach, but also give the p-value. Critical values and p-values are given in the worksheet. It is not necessary to comment on formulas within the Excel worksheet, but you might find it interesting to look at the commands in the cells that contain critical values or p-values.

3. Test the claim that there is no difference in the means for males and females. Again, use 5% level of significance. Apply the equal variances t-test even if you found that the variances are not the same in part 2 above. We want to use the equal variances t-test so that we can compare this with the F-test within ANOVA.Use the critical value approach, but also give the p-value.

4. Give the values of the statistics SSB, SSW, SST, MSB and MSW so that we can compare some of the statistics in the ANOVA printout.Say something about each of these statistics. Don't just write down the values. Show a formula and/or briefly explain what the statistic does.

5. Apply ANOVA to the two samples, females vs males. Format the printout and paste it into your report.

6. Compare the t-test with the ANOVAF-test. Comment on some of the statistics shown in the printout. Are they related to statistics you calculated in parts 3 or 4 above? In particular, is there anything in the printout that wasn't calculated in parts 3 or 4 above?

Data:

Gender	Time
F	30.7
F	31.0
F	32.8
F	37.8
F	40.9
F	43.6
F	46.4
F	47.0
F	47.7
F	47.9
F	49.1
F	49.5
F	50.8
F	50.9
F	51.4
F	51.7
F	51.8
F	52.0
F	52.0
F	53.6
F	53.7
F	54.6
F	56.7
F	56.8
F	57.5
F	59.6
F	60.8
F	63.8
M	37.0
M	40.2
M	40.4
M	42.2
M	42.3
M	42.9
M	43.5
M	44.5
M	46.8
M	47.1
M	47.3
M	47.5
M	47.9
M	48.1
M	49.4
M	50.6
M	50.9
M	52.1
M	52.3
M	52.7
M	53.2
M	53.3
M	54.8
M	54.9
M	55.1
M	56.0
M	56.1
M	56.8
M	59.5
M	61.4
M	62.1
M	69.6
mean_all =	50.010
stdev_all =	7.779
variance_all =	60.50871
n_all =	60