Question: Hello my teacher sent back my assignment and I need help with the revisions: PT 1. Teachers message: #1 - Can you please explain what
Hello my teacher sent back my assignment and I need help with the revisions:
PT 1.
Teachers message:
#1 - Can you please explain what you mean by Log2(x)plug2(18).Also, I'm not sure where K came from.
#2, 3, 4, 8- Please show how you test for extraneous solutions (which you do have here.)
#10, 11, 12 - Be careful with your symbols.* means multiplication.You should have decimals here.
#13 - This is incorrect, but I'm not quite following your work.When there is no base in a log, the base is 10.
#14 - I'm not following your work after 10log(9x1010).What did you have for log(9x1010)?
my assignment:
8. log2(x - 4) + log2(x) = 5
Log2[(x-4)x]=5
25=[x(x-4)]
25=x(x-4)
X(x-4)=32
X2-4x-32=0
X2+4x-8x-32=0
X(x+4)-8(x+4)=0
(x-8)(x+4)=0
X=8 and x=-4
10. log2(x) = 3.87
X=23*87=2(3*87)=14*62
11. log2(2x) = 5.23
2x=2(5*23)=37*5
X=37*5/2=18*75
12. ln(3.1x) = 2.31
3*1x=e2*31=10*07
X=10.07/3*1=3*24
Solve the following problems showing your steps and including the units of measurement.
13. Earthquake intensity is measured by the Richter scale. The formula for the Richter rating of a given quake is given by "R=log[I/I0]" where I0is the "threshold quake", or movement that can barely be detected, and the intensity I is given in terms of multiples of the threshold intensity.
An earthquake was reported to have a Richter number of 5.99. How does the intensity of the earthquake approximately compare with the reference intensity?
Richter scale=R=log[I/I0]
Since R=5*99
5*99=loge[I/I0]
I/I0=e5*99=399*4I-> I0=399*4I
I=I0=*=(3*99)
The first intensity=I
The end intensity= 399I
The intensity increased to 399 times as the first value.
14. "Loudness" is measured in decibels. The formula for the loudness of a sound is given by "Db = 10log[ I / I0]" where I0is the intensity of "threshold sound", or sound that can barely be perceived. How many decibels is a noise with an intensity of I = (9 * 1010)I0?
The loudness=10log[I/I0]
Since I=9x1010I0hence the loudness turns into =10log(I09x1010/9xI010)
=10log(9x1010)=10x9*954=99*54 dB
PT 2.
The other teacher message:
It looks like you misread the exponents on these, but I can't tell when you have exponents and when you don't.
the assignment and my answers:


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