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Use the following scenario and data for questions 21 to 30 Crammer Tools, LLC. makes two products. The availability of three scarce resources limits the production of the products. The profit contribution, resource usage per unit of each product, and availabilities of the resources are given in the following table. Resource 1 2 3 Profit Contribution Resource Usage per Unit Product 1 Product 2 3 2 1 2 6 7 5 4 Availability 180 100 420 The decision variables used in the lincar programming model are X; - number of units of product I to produce I max X; - number of units of product 2 to produce The linear programming model and the graphic solution are given in the following 5x + 4x2 3x + 2 xz 180 1 xy + 2xy S 100 6x, +7x2 5 420 *t20 100 90 80 Feasible region 70 6090 SO 6d 40 50 30 Optimal solution 140 20 20 40 10 30 10 20 20 30 40 5+4x) - 200 50 60 70 3x+223 - 180 80 90 100 110 6x4 + 7 x 420 9+2x - 100 QUESTION 21 X1 and X2, respectively, the slope of a line for the objective Using and C1 C2 to represent the objective coefficients of function can be represented by OG1 C2 O C1 C2 OC2 C1 O none of the above QUESTION 22 The slope of the line representing the equation part of the constraint 3x1 + 2x2 5 180 is 3 2 min 2 win O2 3 nim O none of the above QUESTION 23 The slope of the line representing the equation part of the constraint 6x 1 +7x2 420 is O 6 7 06 7 07 6 7/35 07 6 O none of the above QUESTION 24 The correct inequality used to determine the intervals for the objective coefficients is 06 s 3 2. 7 C2 O 6 3 6. 7 3 2. 03 O none of the above QUESTION 25 Keeping C2 constant at C2-4, the interval for C1 in which the current optimal solution remains optimal is O 24 7S-0256 S 245456 7 Ossas - 24 v 24 54156 7 none of the above QUESTION 26 Keeping C2 constant at C2 = 4, the interval for the net change in C1. represented by AC1, while the current optimal solution remains optimalis 0475-4651 o 11 Sacsi