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core: 2/8 1/4 answered . Question 3 - Write each expression in terms of the tangent function. A compound fraction is a fraction where either the numerator, the denominator, or both are also written as fractions. You can often simplify comes denominator by the same quantity. often simplify compound fractions by multiplying the numerator and sin(I) Part A: - Part A: Multiply the numerator and denominator of the fraction cos (I) itz Hint by four to obtain a simple fraction. Answer: Answer: Part B: Multiply the numerator and denominator of the fraction sin (z) by 12 to obtain a simple fraction. Part B: cos? (I) Answer: Question Help: Message instructor Calculator Answer: Submit Question cos (32) sin (3:) Answer: :" Reflect in ePortfolio Question Help: Message instructor Calculator Submit Question Question 4 RF2_13E_Practice RF2_13E_Practice ~ Score: 1/8 1/5 answered In In-Class Activity 11.B, we saw that cos(2z) = 2cos?(z) - 1. . Question 2 RF2_13E_Practice Part A: Find a formula for sec(21) in terms of cos(I). Score: 1/8 1/5 answered In In-Class Activities 11.C and 11.D. we learned the identities sin?(z) - 2 (1 - cos(2z)) and . Question 3 sec(2z) = cos?(z) - - (1 + cos(2z)). Use these formulas to derive a formula for tan?(z) in terms of In In-Class Activities 1 1.A and 11.B, we used the identities sin(2z) = 2 sin(z)cos(z) and cos(2z). cos (2z) - cos?(z) sin (z). tan (2) Part A: Give a formula Part B: Find a formula for sec(2:) in terms of sec(z). Simplify your answer. Question Help: Message instructor tan(27)= sec(2z) = 2 Calculator Question Help: Message instructor Part B: Multiply the numerator and denominator of your formula in Part A by cos? (2) . and then Calculator implify your answer to give a formula for tan(2z) in terms of tan(z). Submit Question tan(2z) - westion Help: Message Instructor Submit Question : Reflect in eportfolio Activity Details . Task: View this topic " Reflect in efforttobe :" Reflect in ePortfolio . Task: View this topic .Task: View this topic . PhotoC