Help me solve ! Part c

(0%) Problem 9: The acceleration due to gravity on the moon, gM, has one-sixth of the Earth's value, g. A ball is thrown straight up on the Moon, and its total time of flight, meaning the time it takes to return to the Moon's surface, is t = 8.42 s . V. Otheexpertta.com 25% Part (a) What is the numeric value of the magnitude, in meters per squared second, for the acceleration due to gravity on the moon? gM = 1.630 m/s2 Correct! 25% Part (b) Enter an expression for the maximum height achieved by the ball on the moon, hm, in terms of the gravitational acceleration on earth, g, and the total time of flight, tflight. hm = ((1/6 ) g tAight )/8 Correct! $ 25% Part (c) Given the value of the total time of flight in the problem statement, what is the maximum height, in meters, of the ball on the Moon? Grade Summary hm = m Deductions Potential 100% sin( cos tan( 7 8 9 HOME Submissions Attempts remaining: 3 cotan asino acoso E 4 5 6 (0% per attempt) atan( acotan( sinh() 2 3 detailed view 0% cosho tanh() cotanh() + O END